- Mar 22, 2019
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Jö Fahlke authored
The local basis is passed into the local operator kernels as a const reference. That means, its lvalue is not a constant expression. Would we pass it by value, then it's lvalue would be a constant expression (through it's rvalue still would not). Calling a static function of a class throuh an object with the syntax ```c++ lb.size() ``` will evaluate the lvalue of the object. Since that lvalue is not constant when the object was passed by reference, the call cannot be a constant expression. Clang (rightly) complained about this, so write the call as ```c++ LocalBases::size() ``` where a constant expression is required.
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Jö Fahlke authored
This uses our own Q1 local basis implementation that hands out std::array results
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Jö Fahlke authored
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Jö Fahlke authored
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- Mar 21, 2019
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- Mar 20, 2019
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Jö Fahlke authored
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- Mar 17, 2019
- Mar 16, 2019
- Mar 12, 2019
- Mar 09, 2019
- Mar 08, 2019
- Mar 05, 2019
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Jö Fahlke authored
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- Mar 01, 2019